อนุพันธ์

$ y= \frac{4x^2+5}{2+e^{4x}} $

วิธีทำ

\begin{align} & \cssId{Step1}{ \frac{dy}{dx} = \frac{(2+e^{4x} )\frac{d}{dx} (4x^2+5) - (4x^2+5) \frac{d}{dx} (2+e^{4x}) }{(2+e^{4x})^2} } \\ &\cssId{Step2}{= \frac{(2+e^{4x} ) (8x) - (4x^2+5) (4 e^{4x}) }{(2+e^{4x})^2} } \\ \end{align}